https://jak.mazovia.edu.pl/api.php?action=feedcontributions&feedformat=atom&user=LolitaChevalier 2026-10-12T09:14:00Z Wkład użytkownika MediaWiki 1.42.1 https://jak.mazovia.edu.pl/index.php?title=Answers_About_Geometry&diff=758659 2026-09-23T14:09:46Z

<p>LolitaChevalier: </p> <hr /> <div>&lt;br&gt;The [https://www.exeideas.com/?s=perimeter perimeter] is both on the outside and the inside of a shape, [https://sololucky.uk pg slot] as it is [https://www.caringbridge.org/search?q=basically basically] the outside wall/border of a shape and can therefore be viewed from the outsi&lt;br&gt;Read more&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;Math and Arithmetic&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;+2&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;What is the circumference of a circle if its area is 81π?&lt;br&gt;&lt;br&gt;&lt;br&gt;Asked by Anonymous&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;C = 81 pi = 2pi r&lt;br&gt;&lt;br&gt;Hence&lt;br&gt;&lt;br&gt;2 pi r = 81pi&lt;br&gt;&lt;br&gt;r = 81 pi / 2 pi&lt;br&gt;&lt;br&gt;Cancel down&lt;br&gt;&lt;br&gt;r = 40.5&lt;br&gt;&lt;br&gt;A = pi r^(2)&lt;br&gt;&lt;br&gt;A = pi ( 40.5)^(2)&lt;br&gt;&lt;br&gt;A = 1640.25 pi units^(2)&lt;br&gt;&lt;br&gt;</div>

LolitaChevalier https://jak.mazovia.edu.pl/index.php?title=U%C5%BCytkownik:LolitaChevalier&diff=758657 2026-09-23T14:09:43Z

<p>LolitaChevalier: Utworzono nową stronę &quot;I&#039;m Lolita and I live with my husband and our 3 children in Saint-Priest, in the CENTRE south part. My hobbies are Book collecting, Lapidary and Speed skating.&lt;br&gt;&lt;br&gt;my web blog: [https://sololucky.uk pg slot]&quot;</p> <hr /> <div>I'm Lolita and I live with my husband and our 3 children in Saint-Priest, in the CENTRE south part. My hobbies are Book collecting, Lapidary and Speed skating.&lt;br&gt;&lt;br&gt;my web blog: [https://sololucky.uk pg slot]</div>

LolitaChevalier